Write a Python program to check whether a given year is a leap year or not.

Input-Output Examples

Example 1:
Input: Enter a year: 2024
Output: 2024 is a leap year.
Example 2:
Input: Enter a year: 2023
Output: 2023 is not a leap year.

Algorithm to check whether a given year is leap year or not

1. Start
2. Take input: Prompt the user to enter a year.
3. Check the year:
   • If the year is divisible by 4:
     • If the year is divisible by 100, check if it is also divisible by 400. If yes, it is a leap year.
     • Otherwise, it is a leap year.
   • If not divisible by 4, it is not a leap year.
4. Display the result: Print whether the year is a leap year or not.
5. End

Python Program to check whether a year is leap year or not

# Python program to check if a year is a leap year

# Take input from the user
year = int(input("Enter a year: "))

# Check if the year is a leap year
if (year % 4 == 0):
    if (year % 100 == 0):
        if (year % 400 == 0):
            print(f"{year} is a leap year.")
        else:
            print(f"{year} is not a leap year.")
    else:
        print(f"{year} is a leap year.")
else:
    print(f"{year} is not a leap year.")

Code Explanation

1. Taking input from the user:
   The program uses the input() function to take a year as input from the user. The input is converted to an integer using int().
2. Checking if the year is a leap year:
   The program checks whether the year is divisible by 4, 100, and 400 using conditional statements:
   • If the year is divisible by 4, it may be a leap year.
   • If it is divisible by 100, the program checks if it is divisible by 400 as well. If both conditions are satisfied, it is a leap year; otherwise, it is not.
   • If it is divisible by 4 but not by 100, it is a leap year.
3. Displaying the output:
   The print() function displays whether the year is a leap year or not using an f-string to format the output.